Question

cotA /cosecA+1 + cosecA +1/cotA = 2secA

Answer 1

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Answer 2

cotA/(cosecA+1) + (cosecA+1)/cotA

=cot²A+(cosecA+1)²/cotA(cosecA+1)

=(cot²A+cosec²A+1+2cosecA)/cotA(cosecA+1)

=(2cosec²A+2cosecA)/cotA(cosecA+1)

=2cosecA(cosecA+1)/cotA(cosecA+1)

=2cosecA/cotA

=2×1/sinA×sinA/cosA

=2secA