Question

(cota+coseca-1)/(Cota-coseca+1) = 1+cota/sina

Answer 1

hi!!
here u go.....


cosecA+cotA-1/cosecA+1



we know that, cosec²A-cot²A=1

substituting this in the numerator,

cosecA+cotA-(cosec²A-cot²A)/(cotA-cosecA+1)

x²-y²=(x+y)(x-y)

cosecA+cotA-(cosecA+cotA)(cosecA-cotA)/cotA-cosecA+1)

taking common

(cosecA+cotA)(1-cosecA+cotA)/(cotA-cosecA+1)

cancelling like terms in numerator and denominator we are left with,

cosecA+cotA

= 1/sinA+cosA/sinA

= (1+cosecA)/sinA



ANSWER = (1+cosecA)/sinA


hope it hlps u!!!

Regards,
SAMEERA❤️