Question

coto + coso =M
coto - cos =n
prove that (m²-n²) ^2=16 mn​

Answer 1

$\cot( \alpha ) + \cos( \alpha ) = m > > (i) \\ \cot( \alpha ) - \cos( \alpha ) = n > > (ii)$

$subtracting \: (ii) \: from \: (i) \: we \: get \\ 2 \cos( \alpha ) = m - n \\ \\ adding \: (ii) \: and \: (i) \: we \: get \\ 2 \cot( \alpha ) = m + n$

$multiplying \: (i) \: and \: (ii) \: we \: get \\ ( \cot( \alpha ) + \cos( \alpha ) )( \cot( \alpha ) - \cos( \alpha )) = mn \\ {cot}^{2} \alpha - { \cos}^{2} \alpha = mn$

Answer 2

Step-by-step explanation:

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