coto.cot(60° + 0).cot(60° - 0) = cot30
Answers
Answered by
0
Answer:L.H.S.=cotA+cot(60∘+A)-cot(60∘-A)
=
1
tanA
+
1
tan(60∘+A)
-
1
tan(60∘-A)
=
1
tanA
+
1-tan60∘tanA
tan60∘+tanA
-
1+tan60∘tanA
tan60∘-tanA
=
1
tanA
+
1-
√
3
tanA
√
3
+tanA
-
1+
√
3
tanA
√
3
-tanA
=
1
tanA
+
(1-
√
3
tanA)(
√
3
-tanA)-(1+
√
3
tanA)(
√
3
+tanA)
(
√
3
-tanA)(
√
3
+tanA)
=
1
tanA
+(
-8tanA
3-tan2A
)
=
3-tan2A-8tan2A
tanA(3-tan2A)
=
3(1-3tan2A)
3tanA-tan3A
=
3
tan3A
=3cot3A=R.H.S
Step-by-step explanation:
Answered by
0
Answer:
here's ur answer dude
Step-by-step explanation:
cot 30° = √3 ; cot 60° = 13√
cot 30° + cot 60° 1 + cot 30° cot 60° = 3√+13√1+3√×13√ = (3+1)3√2 = 43√ × 12= 23√
So, cosec 3x = 23√
cosec 3x = cosec 60°
∴ 3x = 60° or x = 20°
hope it helps
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