Question

The base of a container measures 15 cm x 20 cm.
It is placed on a table top. If the weight of the
container is 60 N, what is the pressure exerted by
the container on the table top ? ​

Answer 1

Answer:

Hey!

Area of the base of container A = 15 cm x 20 cm

P = (60 x 10000)/300 = 10000/5 = 2000

-weight-of-the-container-is-60

hope it will be helpful ✌️

Answer 2

$\bf{\underline{\underline{Given\: :}}}$

$\mathsf{\bigstar\:\: Area\: (A) = 15\: cm × 20 \: cm}$

Since, Weight is the force which is attracted towards the earth. Weight can be represented as Force (F)

$\mathsf{\bigstar\:\: Weight\: (F) = 60\:N}$

$\bf{\underline{\underline{To\:find\: :}}}$

$\mathsf{\bigstar\:\: Pressure\: exerted\: by \: the \: contai}$

$\mathsf{-ner \:on \: the\: table\: top\: (P)}$

$\bf{\underline{\underline{Solution\: :}}}$

$\fbox{\mathsf{\red{Pressure = \frac{Force}{Area}}}}$

$\mathsf{\rightarrow\: P = \frac{60 \:N}{15\:cm × 20\:cm}}$

$\mathsf{\rightarrow\: P = \frac{60 \:N}{15 × 10^{-2}\:m × 20 × 10^{-2}\:m}}$

$\mathsf{\rightarrow\: P = \frac{60 \:N}{15 × 20 × 10^{-4}\:m^{2} }}$

$\mathsf{\rightarrow\: P = \frac{\cancel{60} × 10^{4} \: N}{\cancel{15} × \cancel{20} \:m^{2}}}$

$\mathsf{\rightarrow\: P = \frac{\cancel{10^{4}}\: N}{\cancel{5}\:m^{2}}}$

$\mathsf{\rightarrow \: 2 × 10 ^{3} \: Nm^{-2}}$

$\fbox{\Large{\mathtt{\green{\rightarrow P = 2000\: pascal}}}}$