Question

Could someone help me please!!

Answer 1

hey here is your answer
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According to Coulomb's law,
$f = k \frac{(q1)(q2)}{ {r}^{2} } \: \: \: where \: k = 9 \times {10}^{9} newton \: {m}^{2} \\ \\ now \\ 0.075 = 9 \times {10}^{9} \frac{(q1)(q2)}{ {3}^{2} } \\ \\ 75 \times {10}^{ - 3} = 9 \times {10}^{9} \frac{q1)(q2)}{ 9 } \\ \\ {(q1)(q2)} = \frac{75 \times {10}^{ - 3} }{ {10}^{9} } \\ \\ (q1)(q2) = 75 \times {10}^{( - 3 - 9) \: = - 12}$
since,
(q1)(q2)=75×10^-12 and
(q1)+(q2)=20

then ,
(q1)=20-(q2)

now ,
[20-(q2)] × (q2) = 75×10^-12
(q2)^2 - 20(q2) + 75×10^-12 = 0
here, (q2) = 5

then,
(q1)+(q2)=20
(q1)+ 5 =20
(q1)=20-5
(q1)=15
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Hope it may helpful to you plzz mark mr as brainlist