Question

Could you guys prove this picture?

Answer 1

Answer:

consider a body having uniform accelerated motion and it travel distances(s) in time (t), during the time it's velocity changes from v-u

Explanation:

s=1/2×ac×bc+oa×od

s=1/2×t(v-u)+u×t

by using first equation

ast=v-u/a

s=1/2×(v-u)/a×(v-u)+ut

s=1/2×t×(v-u)+u×t

s=1/2vt+1/2vt

s=1/2(v+u)t

from 1st equation of motion

v-u

s=1/2(v+u)×(v-u)/a

2as=(v+u) (v-u)

2as=v2-uv+uv

v2-u2=2as