Question

Could you please tell me the answer

Answer 1

The answer is Option(b) - 4.


Eigenvalues of A^100  = 1^100 = 1

                                      = (-1)^100 = 1

                                      = (0)^100 = 0

Eigenvalues of I + A^100 = 2,2,1.

Determinant will be the product of eigenvalues = 4.


Hope this helps!