Question

coupons numered 1 to 20 are mixed up and then one of them is drawn at random. waht is the probability that the coupon drawn has a number which is a miltiple of 3​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The probability that the coupon drawn has a number which is a multiple of 3​ is 0.3.

Step-by-step explanation:

Given that,

Total number of outcomes = 20

Now, numbers that are multiples of 20 are

3, 6, 9, 12, 15, 18

So, total number of favorable outcomes = 6

Probability of an event is defined as the ratio of  favorable outcomes to the total number of outcomes.

Using this definition,

$P(E)=\frac{n(E)}{n(S)}\\\\P(E)=\frac{6}{20}\\\\P(E)=\frac{3}{10}\\\\P(E)=0.3$

Hence, required probability is 0.3

# Learn More:

Fifteen coupons are numbered 1 to 15. Seven coupons are selected at random, one at a time with replacement. The probability that the largest number appearing on a selected coupon be 9, is:

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