Question

Covert following expression into 'c': 9xy/p+1-1/3(m+n

Answer 1

Answer:

Explanation:

#include<stdio.h>

#include<conio.h>

void main()

{

int result,x,y,p,m,n;

clrscr();

printf("Enter the Value of x");

scanf("%d",&x);

printf("Enter the Value of y");

scanf("%d",&y);

printf("Enter the Value of p");

scanf("%d",&p);

printf("Enter the Value of m");

scanf("%d",&m);

printf("Enter the Value of n");

scanf("%d",&n);

result=(((9*x*y)/(p+1))-(1/(3*(m+n))));

printf("Result=%d",result);

getch();

}

Answer 2

Here is the required C program:

#include<stdio.h>

#include<conio.h>

int main()

{  int result=0,x,y,p,m,n;  

//It is important to initialize result to avoid garbage value.

//Taking inputs for all the variables

printf("Enter the Value of x");

scanf("%d",&x);

printf("Enter the Value of y");

scanf("%d",&y);

printf("Enter the Value of p");

scanf("%d",&p);

printf("Enter the Value of m");

scanf("%d",&m);

printf("Enter the Value of n");

scanf("%d",&n);

//Following the precedence order of operators the result is formulated as:

result=(((9*x*y)/(p+1))-(1/(3*(m+n))));

printf("Result=%d",result);

return 0;

}