cr(oh)3+Io3=cro4+I balance redox reaction
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In this question we will balance Cr(OH) WITH Cro4 2- and Io3 - with I-
Cr(OH)3 GIVES Cr+3 + 3OH-
Hear OH shows that the equation should be balanced in basic medium
Cr+3----->(Cro4)2-
Cr+3----->(Cro4)2- +4H2O
8OH- + Cr+3---->(Cro4)2- + 4H2O
8OH- + cr+3--->4H2O+(Cro4)2-+ 3e- this is our first equation
Now
IO3 - ----->I-
IO3 - +3H2O ----> I- + 6OH-
IO3- + 3H2O + 6e- -----> I- +6OH- Tthis is our second equation
Multiplying first euation with three and second equation with six
We get our equation as
3IO3- + 9H2O+6Cr(OH)3------> 6(Cro4)2- +24H2O + 3I- + 18OH-
Then by simplifying we get he balanced equation as
IO3 - + 3H2O+2Cr(OH)3 -----> 2Cro4 2- 8 H2O +I- 6OH-
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