Question

Create the equation of a line that is perpendicular to 2y=14+(2/3)x and passes through the point (-2.8)

Answer 1

Answer:

3x+4y-26=0

Step-by-step explanation:

given equation is 2y=14+(2/3)x

then u can arrange mathematical order

i.e (2/3)x-2y+14=0

we can find slope

then slope = - a/ b

put a= 2/3; b= -2

slope = -(2/3) × -2 = 4/3.

perpendicular to line is m1×m2=-1

then 4/3×m2=-1

m2 = -(3/4)

then we can find equation

formula is y-y1 = m2(x-x1)

here x1=-2 ;y1=8

we can apply in this above formula,

we get 3x+4y-26=0.

so this is the above question for the answer.

thank you