cricket lover answer. fast..........................
Answers
the first batsman would have hit a 4 in the first ball and then there would have been a no ball and in that 1 run then the next batsman would have hit a six
Hope it helps
Answer:
Ball 1: P1 hits the ball towards the boundary. Batsman runs 3 and there are 4 overthrows.
Umpires have a check and found it 1 run short.
Now, since they ran for three runs, the P2 batsman will take strike for the last ball. As one run was short and overthrow runs are counted in the batsman's favour, P1 will have reached his century courtesy of 2 runs + 4 overthrows, i.e. 6 runs to take him from 94 to 100.
Ball 2: With still a run to get for a win and six for P2's century, P2 hits a six to bring up his respective century and in doing so, seals the match for his side and solves the 2 batsmen each on 94 runs math problem.