cross multiplication method x+y=3 & 2x-3y=26
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Hello friend
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Your answer is in attachment.
I hope it will help you
Thanks
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Heya!!!
↪ Here's your answer friend,
Above equations Can be written as
x + y - 3 = 0 ........(1)
2x - 3y -26 = 0 ...........(2)
On comparing above equations
we get,
a1 = 1, b1 = 1, c1 = -3
a2 = 2, b2 = -3, c2 = -26
Therefore,
By cross multiplication method :
x / b1c2 - b2c1 = y / c1a2 - c2a1 = 1 / a1b2 - a2b1
==> x / 1 x (-26) - (-3)(-3) = y / -3 x 2 - (-26)1 = 1 / 1 (-3) - 2 x 1
==> x / -26 - 9 = y / -6 +26 = 1 / -3 -2
==> x / -35 = y / 20 = 1 / -5
On comparing 1st and 3rd we get,
==> x / -35 = 1 / -5
==> x = 7
and now on comparing 2nd and 3rd we get,
==> y / 20 = 1 / -5
==> y = -4
Therefore, x = 7 and y = -4
⭐ Hope it helps you : ) ⭐
↪ Here's your answer friend,
Above equations Can be written as
x + y - 3 = 0 ........(1)
2x - 3y -26 = 0 ...........(2)
On comparing above equations
we get,
a1 = 1, b1 = 1, c1 = -3
a2 = 2, b2 = -3, c2 = -26
Therefore,
By cross multiplication method :
x / b1c2 - b2c1 = y / c1a2 - c2a1 = 1 / a1b2 - a2b1
==> x / 1 x (-26) - (-3)(-3) = y / -3 x 2 - (-26)1 = 1 / 1 (-3) - 2 x 1
==> x / -26 - 9 = y / -6 +26 = 1 / -3 -2
==> x / -35 = y / 20 = 1 / -5
On comparing 1st and 3rd we get,
==> x / -35 = 1 / -5
==> x = 7
and now on comparing 2nd and 3rd we get,
==> y / 20 = 1 / -5
==> y = -4
Therefore, x = 7 and y = -4
⭐ Hope it helps you : ) ⭐
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