Crystalline CsBr has a bcc structure. Calculate the
unit cell edge length if the density of CsBr crystal is
4.24 g cm . (Atomic masses : Cs=133; Br = 80)
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Answer:
The edge length of the unit cell of CsBr is 55.05 nm
Explanation:
CsBr has BCC structure.
Number of atom in unit cell of BCC (Z) = 42
Density of CsBr=
Edge length = a
Atomic mass of CsBr(M) = 133 g/mol + 80 g/mol = 213 g/mol
Formula used :
where,
= density
Z = number of atom in unit cell
M = atomic mass
= Avogadro's number
a = edge length of unit cell
On substituting all the given values , we will get the value of 'a'.
The edge length of the unit cell of CsBr is 55.05 nm.
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