Question

Cu crystallizes in fcc unit cell with edge length of 495 pm. What is the radius of Cu atom?​

Answer 1

Answer:

Given :-

• Cu crystallizes in fcc unit cell with edge length of 495 pm

To Find :-

Radius of Cu atom

Solution :-

175 pm

Explanation :-

Here we will use the formula of fcc unit cell which is

$\tt \: r = 0.3535 \: \times a$

Here,

R denotes radius

A denotes Edge

$\tt \: r = 0.3535 \times 495 \:$

$\tt \: r = 175 \: pm$

Hence :-

Radius of Cu atom is 175 pm

Answer 2

Explanation:

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$\text{\huge\underline{\red{Question:-}}}$

:$\Rightarrow$ Cu crystallizes in fcc unit cell with edge length of 495 pm. What is the radius of Cu atom?

$\text{\huge\underline{\orange{To\ find:-}}}$

:$\Rightarrow$ We have to find the radius of Cu atom.

$\text{\huge\underline{\green{Given:-}}}$

:$\Rightarrow$ ● Copper crystallizes is unit cell (Face centred cubic).

:$\Rightarrow$ ● Edge length = 495pm.

$\text{\huge\underline{\purple{Solution:-}}}$

$\text{\large\underline{\pink{According\ to\ the\ question:-}}}$

:$\Rightarrow$ Let, the radius of the atom be r and edge length of the cube be a.

:$\Rightarrow$ $\mathrm{Face\ diagonal\ of\ cube\ =\ \sqrt{2a}}$

:$\Rightarrow$ $\mathrm{r\ +\ 2r\ +\ r\ =\ \sqrt{2a}}$

:$\Rightarrow$ $\mathrm{r\ =\ \dfrac{√2a}{4}}$

:$\Rightarrow$ $\mathrm{=\ \dfrac{a}{2√2}}$

:$\Rightarrow$ $\mathrm{=\ \dfrac{495}{2√2}\ pm}$

:$\Rightarrow$ $\mathrm{=\ 175pm.}$

$\mathrm\blue{So,\ the\ radius\ of\ Cu\ atom\ is\ 175pm.}$

$\text{\huge\underline{\bf{Hence\ Verified}}}$

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