cu + hno3 - cu(no3)2 + no2 + h2o balance by ion electron methord
Answers
Answer:
Hey mate Here is your answer
Explanation:
Cu+HNO
3
→Cu(NO
3
)
2
+NO+H
2
O
Ionic equation,
Cu+H
+
+NO
3
−
→Cu
2+
+NO+H
2
O
1st step: Splitting into two half reactions,
(Oxidationhalfreaction)
Cu→Cu
2+
;
(Reductionhalfreaction)
NO
3
−
+H
+
→NO+H
2
O
2nd step: Adding H
+
ions to the side deficient in hydrogen,
Cu→Cu
2+
;NO
3
−
+4H
+
→NO+2H
O
3rd step: Adding electrons to the side deficient in electrons,
Cu→Cu
2+
+2e; NO
3
−
+4H
+
+3e→NO+2H
2
O
4th step: Balancing electrons in both half reactions,
3Cu→3Cu
2+
+6e 2NO
3
−
+8H
+
+6e→2NO+4H
2
O
5th step: Adding both the half reactions,
3Cu+2NO
3
−
+8H
+
→3Cu
2+
+2NO+4H
2
O
Converting it into molecular form,
3Cu+2NO
3
−
+8H
+
+6NO
3
−
→3Cu
2+
+6NO
3
−
+2NO+4H
2
O
or
3Cu+8HNO
3
→3Cu(NO
3
)
2
+2NO+4H
2
O.