Question

Cu(s)+4HNO3(aq)→ Cu(NO3)2(aq)+2NO2(g)+2H2O(l)net ionic equation

Answer 1

Answer:-

Cu(s)=Cu(NO3)2+2 NO2

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Answer 2

The net ionic equation for the reaction of copper with nitric acid is Cu(s) + 2 H+(aq) → Cu2+(aq) + H2O(l).

For the chemical interaction between copper and nitric acid, the balanced equation is:

Cu(s) + 4 HNO3(aq) = Cu(NO3)2(aq), Cu(NO2)(g), and Cu(H2O) (l)

We must separate the soluble ionic compounds into their corresponding ions and eliminate any spectator ions before we can write the net ionic equation (ions that appear on both sides of the equation and do not participate in the reaction). Water and the copper solid are not ions in this reaction and are thus not accounted for in the net ionic equation.

The reaction's ionic equation is as follows:

Cu2+(aq) + 2 NO2(g) + 2 H2O = Cu(s) + 4 H+(aq) + 4 NO3-(aq) (l)

The spectator ions (H+ and NO3-) may now be eliminated from both sides of the equation to get the net ionic equation:

Cu2+(aq) + H2O from Cu(s) + 2 H+(aq) (l)

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