cu2o + cu2s---->cu + so2 balance the equation
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here is ur balanced equation
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The given equation is,
Cu2O(s) + Cu2S(s) → Cu(s) + SO2(g)
= Number of S atom in L.H.S.
= Number of S atom in R.H.S.
= Number of O atom in L.H.S.
= Number of O atom in R.H.S.
= Therefore,
multiply Cu2O by 22Cu2O(s) + Cu2S(s) → Cu(s) + SO2(g)
Now,
this gives total Cu in L.H.S.
= 6Therefore, Cu in R.H.S.
must be multiplied by 6 to give balanced equation.
The balanced equation is
2Cu2O(s) + Cu2S(s) → 6Cu(s) + SO2(g)
Cu2O(s) + Cu2S(s) → Cu(s) + SO2(g)
= Number of S atom in L.H.S.
= Number of S atom in R.H.S.
= Number of O atom in L.H.S.
= Number of O atom in R.H.S.
= Therefore,
multiply Cu2O by 22Cu2O(s) + Cu2S(s) → Cu(s) + SO2(g)
Now,
this gives total Cu in L.H.S.
= 6Therefore, Cu in R.H.S.
must be multiplied by 6 to give balanced equation.
The balanced equation is
2Cu2O(s) + Cu2S(s) → 6Cu(s) + SO2(g)
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