x=√3+√2/√3-√2 and √3-√2/√3+√2 find the value of x^2+y^2
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X= √3+√2÷√3-√2
By rationalizing the deniminator, you get 5+2√6
Y= √3-√2÷√3+√2
By rationalising, you get 5-2√6
X²+Y² = (5+2√6)²+(5-2√6)²
= (25+24+12√6) + (25+24-12√6)
= 49+12√6+49-12√6
= 98
∴x²+y²= 98
By rationalizing the deniminator, you get 5+2√6
Y= √3-√2÷√3+√2
By rationalising, you get 5-2√6
X²+Y² = (5+2√6)²+(5-2√6)²
= (25+24+12√6) + (25+24-12√6)
= 49+12√6+49-12√6
= 98
∴x²+y²= 98
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