Question

Cube of lead with edges measuring 6 cm each is melted and formed into 27 equal cubes what will be the length of the edges of the new cubes

Answer 1

Answer:

volume of first cube= volume of melted cubes

a^3=a^3

6*6*6*=27*a^3

a^3=6*6*6*/27

a^3=2*2*2

a=3√8

a=2cm

edges of new cubes =2cm

Answer 2

Step-by-step explanation:

side/edge of big cube=6cm

volume of cube=(side)^3

=(6)^3

=216cm^3

now,the volume of big cube=volume of 27 small cubes

let the side of each small cube be x

216=27(x)^3

216/27=x^3

8=x^3

2^3=x^3

2=x

therefore the lenght of the edge of each new cube is 2cm.