Question

Cube root of 250 in rationalising factor

Answer 1

hey!
#ur Ans
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first we find prime factors of the number

250 = 2×5×5×5

now

$= > \sqrt{250} = \sqrt{2 \times 5 \times 5 \times 5} \\ \\ = > take \: pair \: of \: number \\ \\ = > \sqrt{250} = 5 \sqrt{2} \: \: ans$

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