Question

cube root of 74088 by prime factorization method​

Answer 1

Answer:

Find the prime factors of 74088

74088/2

37044/2

18522/2

9261/3

3087/3

1029/3

343/7

49/7

7/7

1

note down the factors

2*2*2*3*3*3*7*7*7=74088

now make groups of 3 same no.s(for eg.2*2*2)

and just write the groped no. once.(for eg. for2*2*2=2)

so,

2*3*7=42

thus,cube root of 74088 is 42