Question

(cube root of x^2y) ÷(root of xy^2)

Answer 1

Answer:

x^(1/6)*2y^(1/3) / y

Step-by-step explanation:

(cube root of x^2y) ÷(root of xy^2)

x^(2/3)*2y^(1/3) /  yx^(1/2)

x^(2/3-1/2)*2^(1/3) / y^(1-1/3)

x^(1/6)*2^(1/3) / y^(2/3)

x^(1/6)*2^(1/3)*y^(1/3)/y^(2/3)*y^(1/3)

x^(1/6)*2y^(1/3) / y

Answer 2

$x^(2/3)*2y^(1/3) / yx^(1/2)</p><p>x^(2/3-1/2)*2^(1/3) / y^(1-1/3)</p><p>x^(1/6)*2^(1/3) / y^(2/3)</p><p>x^(1/6)*2^(1/3)*y^(1/3)/y^(2/3)*y^(1/3)</p><p>x^(1/6)*2y^(1/3) / y$