Question

CuCl2+H2S—>CuS+2HCl

Given, 0.25 mole of CuCl2 and 0.01 mole of H2S. Calculate quantity of CuCl2 produced.

Answer 1

Answer:

Probably you are asking quantity of CuS produced. It 0.01 mole.

Explanation:

1 mole of CuCl2 with 1 mole of H2S gives 1 mole of CuS. So, 0.25 mole of CuCl2 with 0.25 mole of H2S gives 0.25 mole of CuS.

But we have only 0.01 mole (less than 0.25 mole of CuCl2) of H2S.

Now see 0.01 mole CuCl2 (out 0.25 mole) and 0.01 mole of H2S will produce 0.01 mole of CuCl2.

And then we will not have H2S remaining to react with excess CuCl2 left.

So, H2S is limiting reagent.

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