Chemistry, asked by gautamsorout2005, 7 months ago

CuFeS2+O2+SiO2=Cu2S+Cu2O+SO2+FeSoO3 balance it​

Answers

Answered by ashmitverma2005
1

Explanation:

4CuFeS2 + 9.5O2 + 4SiO2 ==> Cu2S + 4FeSiO3 +  7SO2 + Cu2O

.........Left...........Right

Cu......4................4...

Fe......4................4...

S.......8................8...

O......27..............27...

Si.....4................4...

 

To put it in a more conventional form, multiply all coefficients by 2 to get whole number of oxygens:

8CuFeS2 + 19O2 + 8SiO2 ==> Cu2S + 8FeSiO3 + 14SO2 + Cu2O

Answered by itzBiharichora
0

Answer:

Hey mate your answer is below..

please mark as Brainliest.

Explanation:

4CuFeS2 + 9.5O2 + 4SiO2 ==> Cu2S + 4FeSiO3 + 7SO2 + Cu2O

.........Left...........Right

Cu......4................4...

Fe......4................4...

S.......8................8...

O......27..............27...

Si.....4................4...

To put it in a more conventional form, multiply all coefficients by 2 to get whole number of oxygens:

8CuFeS2 + 19O2 + 8SiO2 ==> Cu2S + 8FeSiO3 + 14SO2 + Cu2O

Similar questions