Question

Current flowing through 8 resistor ​

Answer 1

Answer:

0.5 A of current flows through the resistor of 8 Ω.

Explanation:

The equivalent resistance of the two 8Ω connected in parallel is,

$R_1=\frac{8\Omega \times8\Omega }{8\Omega +8\Omega }\\=4\Omega$

The equivalent resistance of the circuit is,

$R_eq=4\Omega +4\Omega \\=8\Omega$

The current following in the circuit is,

$I=\frac{V}{R}$

Substituting all known values,

$I=\frac{8\text { V}}{8\Omega }\\=1\text{ A}$

As, 1A get equally divided as the junction of parallel connection as both resistance have the same value, therefore 0.5 A of current flows through the resistor of 8 Ω.

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