Question

Current in 2 ohm resister in which three resister attached first 1ohm sechond 2 ohm and third is 1 ohm.voltage attachhed with first resister is 4 v and second resistor is 2 v

Answer 1

Answer:

Let, R

1

, R

2

and R

3

be the three resistors connected in series across a 12 V battery. I be the current in circuit.

V=IR

V=I(R

1

+R

2

+R

3

)

V=IR

1

+IR

2

+IR

3

..................(1)

Now, given that,

R

1

=1Ω

IR

2

=4V and

P

3

=I

2

R

3

⇒R

3

=

I

2

P

3

,P

3

=12W and V=12V.

Using this values in (1), we get,

12=I(1)+4+I(

I

2

12

)

8=I+

I

12

I

2

+12=8I

I

2

−8I+12=0

Solving for roots we get

I−2=0 or I−6=0

I=2A or I=6A

Explanation:

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