Current in a circuit falls from 5.0A to 0.0A in 0.1 s. If an average emf of 200V
induced, Give an estimate of the self inductance of the circuit
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Initial current, I1=5.0A
Final current, I2=0A
Change in current, dl=I1−I2=5A
Time taken for the charge, t=0.1s
Average emf, e=200V
For self inductance(L) of the coil, we have the relation for average emf as:
e=Ldtdi
L=dtdie
=0.15=4H200
Hence the self inductance of the coil is 4H.
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