Question

Current in a circuit falls from 5.0A to 0.0A in 0.1 s. If an average emf of 200V

induced, Give an estimate of the self inductance of the circuit​

Answer 1

Answer

Initial current, I1​=5.0A

Final current, I2​=0A

Change in current, dl=I1​−I2​=5A

Time taken for the charge, t=0.1s

Average emf, e=200V

For self inductance(L) of the coil, we have the relation for average emf as:

e=Ldtdi​

L=dtdi​e​

=0.15​=4H200​

Hence the self inductance of the coil is 4H.