Question

Current of 4.8 ampere is flowing through a conductor the number of electrons per second will be

Answer 1

Answer:

I = q/t

q= ne

i= ne /t

n = ixt /e

n= 4.8 x1 / 1.6 x 10^ -19

n = 4.8 / 1.6 x 10^-19

n = 3 x 10 ^19

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Answer 2

The number of electrons per second will be $3\times 10^{19}\ electrons$.

Explanation:

It is given that,

Current flowing through the conductor, I = 4.8 A

Time, t = 1 s

Let n is the number of electron per second. Current flowing through the conductor is given by :

$I=\dfrac{q}{t}$

Since, q = ne

$I=\dfrac{ne}{t}$

$n=\dfrac{It}{e}$

$n=\dfrac{4.8\times 1}{1.6\times 10^{-19}}$

$n=3\times 10^{19}\ electrons$

So, the number of electrons per second will be $3\times 10^{19}\ electrons$. Hence, this is the required solution.

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Electric current

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