Question

current of 4 ampere is passed through a straight wire of length 3 cm in a uniform perpendicular magnetic field of 12 tesla what is the magnetic force experienced by the wire​

Answer 1

Answer:

According to my calculations, about 144 × 10^(-2) N.

Explanation:

F(mag) = BILsin90°

B = 12 T

I = 4 A

L = 3 cm = 3 × 10^(-2) m

F = 4 × 3 × 10^(-2) × 12

F = 144 × 10^(-2) N

Make sure to get it verified though. :)

Answer 2

Answer:

F = 1.44 N

Explanation:

Given :

Current ( I )  = 4 A

Length of wire ( L ) = 3 cm

In term of meter : 0.03 m

Angle is 90

Magnetic field ( B )  = 12 T

We have formula for Force :

$\displaystyle{\vec{F}=\vec{B}.IL}\\\\\displaystyle{F = B.I.L\sin\theta$

We know sin 90 = 1

Putting all given values we get

F = 4 × 0.03 × 12 × 1

F = 48 × 0.03

F = 1.44 N

Hence we get Force experienced by the wire​ is  1.44 N .