Math, asked by aria644, 9 months ago

Curved surface area of a cylinder is 44 cm square and circumference of the base is 8.8cm, find the volume of the cylinder.​

Answers

Answered by BrainlyRaaz
24

Given :

  • Curved surface area of a cylinder is 44 cm².
  • Circumference of the base is 8.8cm.

To find :

  • The volume of the cylinder =?

Formula Used :

  • Circumference of circle = 2πr.
  • Curved Surface area of cylinder = 2πrh
  • The volume of a cylinder = πr²h

Step-by-step explanation :

As We know that,

Circumference of circle = 2πr.

And, in the above question it is given that circumference of the base is 8.8cm. So,

2πr = 8.8 cm

πr = 8.8/2

πr = 4.4

r = 4.4 ÷ 22/7

r = 4.4 × 7/22

r = 1.4

Therefore, We got the Radius (r) = 1.4 cm.

Now, As We know that,

Curved Surface area of cylinder = 2πrh

Substituting the values in the above formula, we get,

44 = 8.8 × h [ ∵ 2πr = 8.8]

h = 44/8.8

h = 5

Therefore, We got the value of height (h) = 5 cm.

Now,

The volume of a cylinder = πr²h

Substituting the values in the above formula, we get,

= 22/7 × π × (1.4)² × 5

= 22/7 × π × 1.4 × 1.4 × 5

= 22 × π × 0.2 × 1.4 × 5

= 30.8π

Therefore, The volume of a cylinder = 30.8π cm³.

Answered by Anonymous
29

{\huge{\bf{\red{\underline{Solution:}}}}}

{\bf{\blue{\underline{Given:}}}}

  • Curved surface area of cylinder = 44cm²
  • Circumference of the base =8.8cm

{\bf{\blue{\underline{To\:Find:}}}}

  • Volume of the cylinder =?

{\bf{\blue{\underline{Now:}}}}

  \longrightarrow{\sf{ cimcumference = 2\pi \: r}} \\ \\

  \longrightarrow{\sf{ 8.8 = 2\pi \: r}} \\ \\

 : \implies{\sf{ curved \: surface \: area \: of \: cylinder = 44}} \\ \\

 : \implies{\sf{ 2\pi rh = 44}} \\ \\

 : \implies{\sf{ 2\pi rh = 44}} \\ \\

 : \implies{\sf{ 8.8h = 44}} \\ \\

 : \implies{\sf{ h =  \frac{44}{8.8} }} \\ \\

 : \implies\boxed{\sf{ h =  5}} \\ \\

__________________________________

Also

  \longmapsto{\sf{ 2\pi \: r = 110}} \\ \\

  \longmapsto{\sf{ 2 \times  \frac{22}{7} \times  \: r = 8.8}} \\ \\

  \longmapsto{\sf{   \frac{44}{7} \times  \: r = 8.8}} \\ \\

  \longmapsto{\sf{     \: r = 8.8 \times  \frac{7}{44} }} \\ \\

  \longmapsto{\sf{     \: r = 1.4 }} \\ \\

__________________________________

  \longrightarrow \boxed{\sf{volume \: of \: cylinder \:  = \pi \:  {r}^{2}h }} \\ \\

 : \implies{\sf{ \pi \times ( {1.4)}^{2} \times 5 }} \\ \\

 : \implies{\sf{ \pi \times 1.96 \times 5 }} \\ \\

 : \implies{\sf{ \pi \times 9.8 }} \\ \\

 : \implies{\sf{  \frac{22}{7}  \times 9.8 }} \\ \\

 : \implies{\sf{ 30.799c {m}^{3} }} \\ \\

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