Question

curved surface area of a right circular cylender is 4.4m^2.If the radius if the base of the cylender is 0.7m.Find its height​

Answer 1

Given,

Curved surface area of a right circular cylinder = 4.4 m²

Radius of base of cylinder = 0.7 m

To find,

Height of cylinder.

Solution :

                   ∵ CSA of cylinder = 2πrh

Where, r = radius and h = height.

Now putting values,

⇒ 4.4 = 2 × 22/7 × 0.7 × h

⇒ 4.4 = 2 × 22 × 0.1 × h

⇒ 4.4 = 4.4 × h

⇒ h = 4.4/4.4

⇒ h = 1

∴ Height of cylinder = 1 m.

Answer 2

Answer:

Given :-

• A curved surface area of a right circular cylinder is 4.4 m² and the radius of the base of the cylinder is 0.7 m.

To Find :-

• What is the height of the cylinder.

Formula Used :-

${\purple{\boxed{\large{\bold{C.S.A\: of\: cylinder\: =\: 2{\pi}rh}}}}}$

where,

• r = Radius
• h = Height

Solution :-

Let, the height of the cylinder be h

Given :

• Curved surface area = 4.4 m²
• Radius = 0.7 m

According to the question by using the formula we get,

⇒ $\sf 2 \times \dfrac{22}{7} \times 0.7 \times h =\: 4.4$

⇒ $\sf 2 \times \dfrac{22}{7} \times \dfrac{7}{10} \times h =\: \dfrac{44}{10}$

⇒ $\sf 2 \times 22 \times h =\: 44$

⇒ $\sf h =\: \dfrac{44}{22 \times 2}$

⇒ $\sf h =\: \dfrac{\cancel{44}}{\cancel{44}}$

➠ $\sf\bold{\red{h =\: 1\: m}}$

$\therefore$ The height of the cylinder is 1 m .