Question

the no. of values if c such that the straight line 3x+4y=c touches the curve x^4/2= x+y is:​

Answer 1

hey dude ❣️

Dy/dx of 3x+4y=c = -3/4

and differentiate the curve also w. r. t x

we get

Dy/dx = 2x^3-1

now , 2x^3-1 = -3/4

2x^3 = 1/4

x^3 = 1/8

=> x = 1/2

solving for y , y = -15/32

putting x and y in straight line eq.

u will get only one value of c I. e c = -3/8

hope it works ❤️