Question

Curved surface area of a right circular cylinder is 4.4 m². Ifthe radius of the base of the cylinder is 0.7 m, find its height.

Answer 1

Hello!

• Radius, r = $\bf{0.7\: m}$

Then,

$\sf Curved\: surface\: area = 4.4 \: \sf m^{2} \\ \\ \implies \sf 2πrh = 4.4 \: \sf m^{2} \\ \\ \implies 2 \times \dfrac{22}{7} \times 0.7 \times \sf h = 4.4 \\ \\ \implies \sf 4.4h = 4.4 \\ \\ \implies \sf h = \dfrac{4.4}{4.4} \implies \boxed{\red{\bf{h = 1}}}$

Cheers!

Answer 2

$\bf \large \it{Hey \: User!!!}$

according to the question, CSA of the cylinder is 4.4m² and radius of it's base is 0.7m.

formula of CSA of a cylinder is 2πrh

therefore 2πrh = 4.4m²
>> 2 × 22/7 × 0.7 × h = 4.4m²
>> 44/10 × h = 4.4m²
>> 4.4 × h = 4.4m²
>> h = 4.4/4.4
>> h = 1

hence, the height of the cylinder is 1m.

$\bf \large \it{Cheers!!}$