Question

Cuso4.5h2o percentage of relative humidity kp=4×10^-2 if vapour pressure of water is 30 torr

Answer 1

Answer:

20 degree centigrade = 293 K

The saturation vapour pressure is:

es=Aexp[−BT]es=Aexp[−BT]

where A = 2.53x10^11 Pa and B = 5420 K and T is in Kelvin

Plugging these values, es=2341 Paes=2341 Pa

The Vapour pressure is:

e=es∗RH100e=es∗RH100

So, we have e = 1053.48 Pa

The specific humidity q is given by the relation:

q=0.622e/pq=0.622e/p

Where P is the atmospheric pressure.

Assuming P = 10^5 Pa, then we have q = 6.553 grams of water vapour per kg of air.

The density of air is given by the relation:

ρ=P/[RT]ρ=P/[RT]

where R is 287 J/KgK. Plugging these values, we have ρ=1.1892kg/m3ρ=1.1892kg/m3

The amount of Water per m^3 of air is :

W = density x q

So, we have W = 7.793 grams of water vapour per m^3 of air.

Since, 1000 L = 1 m^3, in one litre of air, we have 7.793 milli grams of water vapour.

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