Cutting a circle into equal sections of a small central angle to find the area of a circle by using A=πr²?
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hope that u will get it
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dθ : 2π = dA : πr^2
then
dA=dθ*πr^2/(2π)
dA=1/2r^2dθ
A=ΣdA = 1/2r^2∫dθ
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////////////////////////////////
dθ : 2π = dA : πr^2
then
dA=dθ*πr^2/(2π)
dA=1/2r^2dθ
A=ΣdA = 1/2r^2∫dθ
///////////////////////////////
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