Question

exercise 3B class 10 by sabtitution method​

Answer 1

Answer:

Solve for x and y:

Question 1:

x + y = 3,

4x – 3y = 26.

Solution:

x + y = 3 ……..(1)

4x – 3y = 26 ……(2)

Isolate x from equation (1), we get

x = 3 – y

Substituting the value of x in equation (2),

4(3 – y) – 3y = 26

12 – 4y – 3y = 26

-7y = 14

y = -2

Solve for x:

x = 3 – y = 3 – (-2) = 5

Answer: x = 5 and y = -2

Answer 2

Step-by-step explanation:

x + y = 3 (i)

4x-3y = 26 (ii)

From(i),x= 3-y

substituting the value of x in (ii)

4 (3-y) - 3y = 26

=>12 - 4y - 3y = 26

-7y = 26 -12 = 14

y = -2

x = 3, y = 3 (-2) = 3 + 2 = 5

Hence , X= 5, y = -2

I hope I'll help you