Question

cyclist starts from rest and acceleration at the rate of 2 metre per second square what will be his velocity after 5 seconds​

Answer 1

Given :

• Initial velocity, u = 0 m/s

• Acceleration, a = 2 m/s²

• Time, t = 5 seconds

To find :

• Velocity, v

According to the question,

By using Newtons first equation of motion,

→ v = u + at

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

→ Substituting the values,

→ v = 0 + 2 × 5

→ v = 0 + 10

→ v = 10

So,the velocity is 10 m/s.

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More formulas :

Newton's first equation of motion :

• v = u + at

Newton's second equation of motion :

• s = ut + ½ at²

Newton's third equation of motion :

• v² = u² + 2as

Answer 2

Answer:

$\huge \fbox {Given}$

$\sf initial \: velocity \: (u) = 0 \: mps$

$\sf \: Acceleration \: (a) = 2 \: mps²$

$\sf \: time \: taken(t) = 5 \: sec$

$\huge \fbox {To \: find}$

$\sf \: velocity \: of \: cyclist \: (v)$

$\huge \fbox {Answer}$

Here, we will apply newton first Equation.

$\huge \bf \: v \: = u + at$

Putting values

$\sf \: v \: = 0 + 2 (5)$

$\sf \: v \: = 0 + 2 \times 5$

$\sf \: v \: = 0 + 10$

$\sf \: v \: = 10 \: mps$

$\bf \therefore \: velocity \: of \: cyclist \: = 10 \: mps$

Learn more

Newton second equation

$\sf \: s \: = ut + \dfrac{1}{2} \times at²$

Newton third Equation

$\sf \: v { }^{2} = {u}^{2} + 2as$