Cylinder is inserted in a sphere d/h = 2/3. find the surface area of the cylinder
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given
d=2
r=2/2=1
h=3
A/q
r=1
h=3
therefore
area of the cylinder=2×22÷7×1(1+3)
=44÷7×4
=176÷7=25.50
d=2
r=2/2=1
h=3
A/q
r=1
h=3
therefore
area of the cylinder=2×22÷7×1(1+3)
=44÷7×4
=176÷7=25.50
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