Question

cylindrical tub whose diameter is 12 cm and height is 15 CM the whole ice cream is to be divided into 10 children in equal ice cream cone with conical base surmounted by a hemispherical top if the height of conical portion is twice the diameter of base find the diameter of conical part of ice cream

Answer 1

Answer:

Diameter of cylindrical tub, 12cm

Radius, R = 12/2 = 6cm

Height, H = 15cm

Volume of cylindrical = π R2H

= 22/7 x 6 x 6 x 15

For conical portion, let radius, r and diameter, d cm

Height = 2d = 4r

For hemisphere part r1 = r cm

Total volume of ice cream = vol. of cone + vol. of hemisphere

= 1/3 π r2h + 2/3 π r13

= 1/3 π r2 (h+2r) (because r1=r)

= 1/3 x 22/7 x r2 x (4r+2r)

= 44/7 x  r3

Therefore, 10 x 44/7 x  r3 = 22/7 x 6 x 6 x 15

r3        = 22/7 x 6 x 6 x 15 x 7/44 x 1/10  

r3         = 27

r = 3 cm

d = 6 cm

Answer 2

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