Question

(D) 0 m/sIn the figure shown the velocity of lift is 2 m/s while string is winding on the motor shaft with velocit2 m/s and block Ais moving downwards with a velocity of 2 m/s, then find out the velocity of block B12m/sBm A2m/s!(C) 4 m/s1) 2 m/s(B) 2 m/s(D) 8 m/s​

Answer 1

Answer:

As the options are not clear.

The correct answer will be  8 m/s

Explanation:

According to the problem the velocity of the lift is 2 m/s

the velocity of the wind v(w) is 2 m/s

Block A is moving downward with the velocity v(A)   2 m/s

Now if we apply pseudo code method for the block A

then the velocity of block b

V(B)= v(w)+ v(w1)+ v(A)+ v(A1) = 2+2+2+2

= 8 m/s