Question

(D) 13
The equation x2 - 8x + k = 0 has real and distinct roots if
(A) k = 16
(B) k> 16
(C) k = 8
(D) k< 16​

Answer 1

Answer:

Real and distinct root means

b^2-4ac > 0

8^2-4×1×k > 0

64 - 4k > 0

-4k < -64

k < 16

So, option (D) is correct

Answer 2

Answer:

K <16

Step-by-step explanation:

As we know that for real and distinct roots discriminant must be greater than 0

So ,

D = √b²-4ac >0

Here from equation x²-8x+k

b = -8 and a = 1 and c = k

So , √ (-8)²-4*1*k > 0

√64 - 4k> 0

Squaring both side .

64- 4k > 0

K < 16

So option " D "will be correct answer !

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Hope it's helpful