Question

d^2-10d+25 find the zeroes of the polynomial

Answer 1

d^2 - 10d + 25
d^2 - 2*5*d+25
Now this expression is of the form a^2 - 2ab + b^2 = (a-b)^2

So, the above Expression becomes

(d - 5)^2 = 0
So
d-5 = 0
d = 5

Hence, the zeroes of the polynomial are 5 and 5.

Answer 2

d^2 - 10d + 25 = 0

d^2 - ( 5 + 5 )d + 25 = 0

d^2 - 5d - 5d + 25 = 0

d( d - 5 ) - 5( d - 5 ) = 0

( d - 5 ) ( d - 5 ) = 0

( d - 5 ) ^2 = 0

( d - 5 ) = 0



$\boxed{ \bold{ \underline{ \: d = 5}}}$