Question

(d) 2.136x1028
23. If the components of air are nitrogen (78%), oxygen (20%), Argon (1%) and carbon dioxide 1% by
volume, what would be the molecular mass of air in amu?
Options
(a) 523618
(b) 29.08
(c) 38.818
(d) 42.414​

Answer 1

Answer:

ANSWER

1 mole of sample of air, means total volume= 22.4l

0.78 mol N2=21.84gm N2

0.21 mol O2=6.72gm O2

0.01 mol Ar=0.4gm Ar

Total mass= 28.96gm

Density= 22.428.96=1.29gm/lit .