Math, asked by vaidehivedjena, 7 months ago

(d) 3x2 + 2y2 + z2 + 2Vā
$3 {x}^{2} + {2y +}^{2} + {z}^{2} + 2 \sqrt{6xy - 2 \sqrt{2yz } } - \sqrt{zx}$
xy - 212yz - 2/3zx

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Answered by gs4900331

0

Answer:

whatis this math i don't like me.....sorry...

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