Math, asked by mehakjain531, 2 months ago

D^4y-32D^2y+256=0 find solutions​

Answers

Answered by manojpetal
2

Step-by-step explanation:

D^4y -32D^2y +256 = 0

or, (D^2y)²- 2× 16 D^2y +16²= 0

or, (D^2y-16)²= 0

or, D^2y -16= 0

or, D^2y = 16

or D^y = 4

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