Question

d. A calorimeter has mass 100 g and
specific heat 0.1 kcal/ kg °C. It
contains 250 gm of liquid at 30°C
having specific heat of 0.4 kcal/kg
°C. If we drop a piece of ice of mass
10 g at 0 °C, What will be the
temperature of the mixture?
Answer : 20.8 °C​

Answer 1

Answer:

A calorimeter has mass 100 gram and specific heat 0.1 kilo calorie per kilogram degree Celsius if contains 250 kilogram of liquid at 30 degree Celsius having specific heat of 0.4 kilo calorie per kilogram degree Celsius if we drop a space a piece of Ice and mass 10 gram at zero degree celsius what will be the temperature of the mixture

Answer 2

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Let the final temperature of the mixture be T.

Amount of heat required in converting 10 g ice to 0°C to water at 0°C =

10×80=800 cal

Total amount of heat required in converting 10 g water to 0°C to water at T°C =

10×1×T=10T

Total heat energy required to convert 10 g ice at 0°C to water at T°C = 800 + 10T

Amount of heat released to raise the temperature of calorimeter at 30°C to T°C

100×0.1×(30−T)=10(30−T)

Amount of heat released to raise the temperature of 250g of eater at 30°C to T°C =

250×0.4×(30−T)=100(30−T)

Total amount of heat released in the process =

110(30−T)

Using the principle of calorimetry, we have

110(30−T)= 800 + 10T

⇒T=20.83°C