d. A stone thrown vertically upwards with
initial velocity u reaches a height 'h'
before coming down. Show that the
time taken to go up is same as the time
taken to come down.
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in the 1st case u1=u1 v1=0 and t=t1
distance is constant in both the cases
v=u+at=0=u+a×t1_1...
-u=-at
for 2nd case v1=u2=0
v=u+at
v2=at(for 2nd case)
by substituting the values of u1 and v2 in equation v=u-at in both cases we get speed of both are equal
therefore t=d/speed (as speed and d are constant in both cases t1=t2.
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