Math, asked by dk3555693, 3 months ago

(D) all of these
14. Solution of the differential equation p2-8p+15​

Answers

Answered by xSoyaibImtiazAhmedx
2

\Huge\underline{\overline{\mid\star{\sf{\pink{S∅LUTI∅Ñ}}\star\mid}}}

p² +8p+15

= p²+5p+3p+15

= p(p+5)+3(p+5)

= (p+5)(p+3)

p² +8p+15 will result zero , when

(p+5)(p+3)=0

=> p+5 =0. or. p+3 = 0

=> p=-5. => p=-3

So , the zeros of the quadratic polynomial are -5 and -3

Similar questions